Which of the following will have three stereo | vedclass

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(A) To determine the number of stereoisomers:$(i)$ $[Cr(NO_3)_3(NH_3)_3]$ is of the type $[MA_3B_3]$,which exhibits facial $(fac)$ and meridional $(me

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$iii, iv$

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(A) To determine the number of stereoisomers:$(i)$ $[Cr(NO_3)_3(NH_3)_3]$ is of the type $[MA_3B_3]$,which exhibits facial $(fac)$ and meridional $(mer)$ isomerism. It has $2$ stereoisomers.$(ii)$ $K_3[Co(C_2O_4)_3]$ is of the type $[M(AA)_3]$. It exhibits optical isomerism ($d$ and $l$ forms). It has $2$ stereoisomers.$(iii)$ $K_3[CoCl_2(C_2O_4)_2]$ is of the type $[M(AA)_2B_2]$. It exhibits cis-trans isomerism. The cis-form is optically active ($d$ and $l$),while the trans-form is optically inactive. Total stereoisomers = $3$ $(cis-d, cis-l, trans)$.$(iv)$ $[CoBrCl(en)_2]$ is of the type $[M(AA)_2BC]$. It exhibits cis-trans isomerism. The cis-form is optically active ($d$ and $l$),while the trans-form is optically inactive. Total stereoisomers = $3$ $(cis-d, cis-l, trans)$.Thus,$(iii)$ and $(iv)$ have $3$ stereoisomeric forms.

List-$I$ (Complexes)	List-$II$ (Types)
$a$. $[Co(NH_3)_5NO_2]Cl_2$ and $[Co(NH_3)_5ONO]Cl_2$	$i$. Linkage isomerism
$b$. $[Cr(NH_3)_6][Co(CN)_6]$ and $[Cr(CN)_6][Co(NH_3)_6]$	$ii$. Coordination isomerism
$c$. $[Co(NH_3)_5(SO_4)]Br$ and $[Co(NH_3)_5Br]SO_4$	$iii$. Ionisation isomerism
$d$. $[Cr(H_2O)_6]Cl_3$ and $[Cr(H_2O)_5Cl]Cl_2 \cdot H_2O$	$iv$. Solvate isomerism

Which of the following will have three stereoisomeric forms?
$(i)$ $[Cr(NO_3)_3(NH_3)_3]$
$(ii)$ $K_3[Co(C_2O_4)_3]$
$(iii)$ $K_3[CoCl_2(C_2O_4)_2]$
$(iv)$ $[CoBrCl(en)_2]$

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Which of the following will have three stereoisomeric forms?$(i)$ $[Cr(NO_3)_3(NH_3)_3]$$(ii)$ $K_3[Co(C_2O_4)_3]$$(iii)$ $K_3[CoCl_2(C_2O_4)_2]$$(iv)$ $[CoBrCl(en)_2]$